Spaceless triangular sterric pattern

//c++ program to display pattern like that

//user only enter the size
#include <iostream>
using namespace std;
int main()
{
 int size,temp_variable;  //declaring variables
 cout<<"Enter size = ";  //asking for output
 cin>>size;     //input
 temp_variable=size;   //storing sizze in temporary variable
 if(size>0)
 {
  for(int i=1;i<=size;i++)   //outer loop controlling number of rows
  {
   for(int j=1;j<=temp_variable;j++)  //inner loop controlling number of columns
   {
    cout<<"*";
   }
   temp_variable--;   //applying decrement
   cout<<endl;
  }
 }
 else
 {
  cout<<"PLease enter size greater than zero.\n";
 }
 return 0;
}

Triangular steric pattern

//c++ program to display pattern like that

#include <iostream>
using namespace std;
int main()
{
 int size,temp_variable;   //declaring variables
 cout<<"Enter size = ";   //asking for input
 cin>>size;      //input
 temp_variable=size;    //store size in temporary variable
 if(size>0)
 {
  for(int i=1;i<=size;i++)   //outer loop controlling number of rows
  {
   for(int j=1;j<=temp_variable;j++)  //inner loop controlling number of columns
   {
    cout<<"* ";
   }
   temp_variable--;     //applying decrement
   cout<<endl;
  }
 }
 else
 {
  cout<<"Please enter size greater than zero.\n";
 }
 return 0;
}

Triangular number pattern

//c++ program to dispaly a pattern like that

//so user only has to enter the size of pattern
#include <iostream>
using namespace std;
int main()
{
 int size,temp_size;    //declaring variable
 cout<<"Enter size  = ";   //asking for output
 cin>>size;      //giving input
 temp_size=size;      //store size in a temporary variable named temp_size
 for(int i=1;i<=size;i++)    //outer loop controllin number of rows
 {
  for(int j=1;j<=temp_size;j++)  //inner loop controlling number of columns
  {
   cout<<j<<" ";
  }
  temp_size--;     //decrement
  cout<<endl;
 }
 return 0;
}

Lower triangular number pattern

//c++ program to display a pattern like that

//so user only has to enter size
#include <iostream>
using namespace std;
int main()
{
 int size;        //declaring variable
 cout<<"Enter size = ";     //asking for input
 cin>>size;        //giving input(size)
 if(size>0)        // applying check
 {
  for(int i=1;i<=size;i++)    //applying outer loop which will controll number of rows
  {
   for(int j=1;j<=i;j++)    //applying inner loop whiuch will controll number of columns
   {
   cout<<j<<" ";
  }
  cout<<endl;
  }
 }
 else
 {
  cout<<"You have enter wrong size\n";   //condition for invalid input
 }
 return 0;
}

To find the nature and value of roots of quadratic equation except for complex roots

/*c++ Program to find the nature of roots and value of
roots of a quadratic equation.User has to enter the values of coefficients
of x^2,x and the value of constant*/

#include<iostream>
#include<cmath>
using namespace std;
int main()
{
  float a,b,constt,discre,root1,root2,k;  //declaring variables
  do
  {
  cout<<"Enter coeffitient value of x^2 = ";
     cin>>a;         //input the value of a the coeffitient of x^2
  }while(a==0);        //checking condition
  cout<<"Enter coeffitient value of x = ";  //asking to give input (value of coeffitient of x)
  cin>>b;          //input the (value of coeffitient of x)
  cout<<"Enter value of constant = ";    //asking to give value of constant
  cin>>constt;          //input the value of constant
  discre=pow(b,2)-4*a*constt;      //k is used as to store a temperarly intermediate result
  k=sqrt(discre);
   if(discre==0)
   {
     root1=(-b+k)/(2*a);  
     cout<<"The equation has a single(repeated) root\n\n";
     cout<<"first root = "<<root1<<endl;
   }
  else if(discre>0)
  {  
   root1=(-b+k)/(2*a);
   root2=(-b-k)/(2*a);
   cout<<"Equation has two real roots.\n\n";
      cout<<"First real root = "<<root1<<endl;
      cout<<"Second real root = "<<root2<<endl;
     }
  else
  {
    cout<<"The equation has two complex roots\n\n";
  }
 return 0;
}

4. Write a program that takes a character from A to Z and convert it into lower-case character. (use type casting)

1. Write a program that takes a character from A to Z and convert it into lower-case character. (use type casting)

#include <iostream>

using namespace std;

int main()

{

char x; //introducing variable

int value;

cout<<"Enter x = "; //asking for input

cin>>x; //giving input

value=static_cast<int>(x); //typecast char int int datatype

x=value+32; //addind 32 in upper case to get lowercase

value=static_cast<char>(x); //typecast int into char datatype

cout<<"The lower case of upper case = "<<x<<endl; //getting lower case in output

return 0;

}

display a * pattern bynb setwidth manipulator

　

1. Write a program to display the following pattern using setw:

* 

                      *** 

                    ***** 

                  *******

#include <iostream>

#include <iomanip> //introducing library for setw() manipulator

using namespace std;

int main()



{

cout<<setw(6)<<"*\n" //setting set width

<<setw(7)<<"***\n" //setting set width

<<setw(8)<<"*****\n" //setting set width

<<setw(9)<<"*******\n"; //setting set width

return 0;



}

Find the no of cookies!!!!!!!!!!

1. A bag of cookies holds 40 cookies. The calorie information on the bag claims that there are 10 “servings” in the bag and that a serving equals 300 calories. Write a program that asks the user to input his/her name and how many cookies he or she actually ate and then reports how many total calories were consumed.

1. Write a program that asks for five test scores. The program should calculate the average test score and display it. The number displayed should be formatted in fixed-point notation, with one decimal point of precision. (use of while loop is optional)

1.      Write a program that asks for five test scores. The program should calculate the average test score and display it. The number displayed should be formatted in fixed-point notation, with one decimal point of precision. (use of while loop is optional)

#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
int s1,s2,s3,s4,s5;
double avg,sum;
cout<<"Enter first test score = ";
cin>>s1;
cout<<"Enter 2nd test score = ";
cin>>s2;
cout<<"Enter 3rd test score = ";
cin>>s3;
cout<<"Enter 4rth test score = ";
cin>>s4;
    cout<<"Enter fifth test score = ";
cin>>s5;
sum=s1+s2+s3+s4+s5;
avg=sum/5;
cout<<"The average= "<<setprecision(1)<<fixed<<avg<<endl;
return 0;
}

Use of setwidth operator in c++

Use of setwidth operator in c++




/*use of setw() output formator usually it is automatically right
sewidth which are formatted numbers are written on right side spaces are placed at 
left this is right justified but adding only word left it will become 
left justified we have to only add         <<left     before <<setw()<<value;
numbers are automatically riht justified but if we want to place right word just like
<<right     before stw()<<value    */
 /*in order to make following program right justified just remove     <<left    from syntax */

#include <iostream>
using namespace std;
#include <iomanip>
int main()
{
int n1=3,n2=4,n3=435,n4=2453,n5=4535,
n6=43232,n7=231534,n8=25434,n9=2423;
cout<<left<<setw(7)<<n1<<left<<setw(7)<<n2<<left<<setw(7)<<n3<<endl
<<left<<setw(7)<<n4<<left<<setw(7)<<n5<<left<<setw(7)<<n6<<endl
<<left<<setw(7)<<n7<<left<<setw(7)<<n8<<left<<setw(7)<<n9;
return 0;

}

c++ program to find factorial of any positive number;

c++ program to find factorial of any positive number;


/*This is a c++ program to find factorial of any number given by user.
we use while loop in it.
store 1 in fact then store fact*i=1*1 in it
when i will come after inrement 2 will store in it
when i will 3 and come ,2 is stored stored in fact now 2*3= 6 will store in it
It will going on till i becomes equal to num*/

#include <iostream> //library
using namespace std;
int main() //tell about main function the execution will start from here
{
int i=1,num; //we declare num and inizialize the count i.e i 
double fact=1; //we also start fact from 1
cout<<"Enter number = "; //display message on console
cin>>num; //input number
if (num>0) //applying if so that number should be positive
{
while (i<=num) //applying condion that number should equal to or greater than i
{
fact=fact*i; //now store the product value of fact*i in fact
i++;
}
cout<<"The Factorial = "<<fact<<endl;   //we should use {} braces to enclose the body of if,else if,else ;
} //loop and condition in parenthesis ()
else if (num==0) //we can use if separatly but no else if,else
{
cout<<"The factorial = 1"<<endl;
}
else if (num<0)
{
cout<<"Please enter positive number.\n";
}
return 0;
}

The c++ program to find the size of data types and then tell also about the data type

Q1) suppose you are programmer but you have no user manual to see the size of different data types like int, double , float , char  and long. Write a programm that will calculate the size of this data types and display data type on screen.

#include <iostream>
using namespace std;
int main()
{
int in,size_in;
float fl,size_fl;
double db,size_db;
   long lg,size_lg;
short sh,size_sh;
cout<<"Enter int = ";
cin>>in;
size_in=sizeof (in);
cout<<"The size of int(data type) = "<<size_in<<endl<<"Data type is int. "<<endl<<endl;
cout<<"Enter float = ";
cin>>fl;
size_fl=sizeof (fl);
cout<<"The size of float(data type) = "<<size_fl<<endl<<"Data type is float. "<<endl<<endl;
cout<<"Enter double = ";
cin>>db;
size_db=sizeof (db);
cout<<"The size of double(data type) = "<<db<<endl<<"Data type is double."<<endl<<endl;
cout<<"Enter long = ";
cin>>lg;
size_lg=sizeof (lg);
cout<<"The size of long(data type) = "<<size_lg<<endl<<"Data type is long."<<endl<<endl;
cout<<"Enter short = ";
cin>>sh;
size_sh=sizeof (sh);
cout<<"The size of short(data type) = "<<size_sh<<endl<<"Data type is short"<<endl<<endl;
return 0;
}

c++ program to find size of data type int

#include <iostream>

using namespace std;

int main()



{

int in,size;

size=sizeof (in);

cout<<"size ="<<size;

return 0;

}

Q9) Take a number as an input from the user from the following program and then display that number.

#include <iostream>
using namespace std;
int main()
{
 float num;
 cin>>num;
 cout<<"The number = "<<num;
 return 0;
}

           

 

Q8) A car holds 12 gallons and can travel 350 miles before refueling. Write a program that calculates the number of miles per gallon the car gets. Display the result on the screen.

Hint: use the following formula to calculate miles per gallon (MPG)

MPG = Miles Driven / Gallon of Gas Used.

 

 

 

 

 

 

#include <iostream>
using namespace std;
int main()
{
 int gallons,miles;
 double mpg;
 gallons=12;
 miles=350;
 mpg=miles/gallons;
 cout<<"MPG = "<<mpg<<endl;
 return 0;
}

Q6) Write a program that displays the following pattern on screen.

           *

               ***

             *****                      

          *******

#include <iostream>
using namespace std;
int main()
{
cout<<"   *\n"<<"  ***\n"<<" *****\n"<<"*******\n";
return 0;
}

Q5) Write a program that displays the following pieces of information, each on separate line:

Your name

Your Degree

Your section

Your Department

Your university

 

Use single cout statement to do this.

 

#include <iostream>
using namespace std;
int main()
{
 cout<<"Your Name \n"<<"Your Degree \n"<<"Your Section \n"<<"Your Department \n"<<"Your University \n";
 return 0;
}

Q10) Modify the program of first question by taking the speed and time from the user as input.

 #include <iostream>
using namespace std;
int main()
{
 float speed,distance,time;
 cout<<"Enter speed = ";
 cin>>speed;
 cout<<"Enter time = ";
 cin>>time;
 distance=time*speed;
 cout<<"The distance = "<<distance<<endl;
 return 0;
}

Q4) Write a program that stores the following values in five different variable 28, 32.37,24 and 33. The program should calculate the sum of these variables and store the result in separate variable named sum. Then program should divide sum variable by 5 to get the average. Display average on screen.

#include <iostream>
using namespace std;
int main()
{
int a,b,c,d,e,sum;
double avg;
a=28;
b=32;
c=35;
d=24;
e=33;
{
sum=a+b+c+d+e;
}
{
avg=sum/5;
}
cout<<"Average of five numbers = "<<avg<<endl;
return 0;
}

Q3) Write a program that computes the tax and tip on a restaurant bill for a patron with a $44.75 meal charge. The tax should be 6.75 percent of the meal cost. The tip should be 15 percent of the total after adding the tax. Display the meal cost, tax amount, tip amount and total bill on the screen.

#include <iostream>
using namespace std;
int main()
{
double meal_cost,tax,new_bill,tip,total_bill;
meal_cost=44.75;
cout<<"Meal cost = "<<meal_cost<<endl;
{
tax=6.75/100*44.75;
}
cout<<"tax = "<<tax<<endl;
{
new_bill = meal_cost + tax;
}
{
tip =  (new_bill/100)*15;
}
cout<<"tip = "<<tip<<endl;
{
total_bill= tax + meal_cost + tip;
}
cout<<"total bill = "<<total_bill<<endl;
return 0;
}

c++ program to find pressure when force = 172.5 and area = 27.5


#include <iostream>
using namespace std;
int main()
{
float force,area,pressure;
force=172.5;
area=27.5;
pressure=force*area;
cout<<"The pressure = "<<pressure<<endl;
return 0;
}

c++ program to find distance when speed = 30 time = 10

#include <iostream>
using namespace std;
int main()
{
int speed,time,distance;
speed=30;
time=10;
{
distance=speed*time;
}
cout<<"distance = "<<distance<<endl;
return 0;
}

c++ program to find greater number of two numbers




include <iostream>
using namespace std;
int main()
{
int a,b;
cout<<"enter a = \n"<<"enter b = \n";
cin>>a>>b;
if(a>b)
cout<<"a is greater than b";
else
{
cout<<"b is greater than a ";
}
return 0;
}

C++ program for the division of sum of square of two numbers to square of another number

C++ program for the division of sum of square of two numbers to square of another number



#include <iostream>
#include <cmath>
using namespace std;
int main()
{
    float x,y,z;
    double div;
    cout<<"enter x = \n";
    cin>>x;
    cout<<"Enter y = \n";
    cin>>y;
    cout<<"Enter z = \n";
    cin>>z;
    {
        x=pow(x,2);
        y=pow(y,2);
        z=pow(z,2);
    }
    {
        div=(x+y)/z;
    }
    cout<<"The division of sum of square of two numbers to square of another number = "<<div;
    return 0;
}

c++ program to find slope of a graph:

#include <iostream>
using namespace std;
int main()
{
    float x1,x2,y1,y2;
    double slope;
    cout<<" Enter value of x1 = \n";
        cin>>x1;
    cout<<"Enter value of x2 = \n";
    cin>>x2;
    cout<<"Enter value of y1 = \n";
    cin>>y1;
    cout<<"Enter value of y2 = \n";
    cin>>y2;
    {
        slope=(y2-y1)/(x2-x1);
        cout<<"The slope is = "<<slope;
    }
        return 0;
}

Block a Website on Your PC

1. Open Windows Explorer and navigate to C:\Windows\System32\drivers\etc. If Windows is not installed on C:, substitute the appropriate drive letter.
2. Double-click hosts, and select Notepad when Windows prompts you to choose a program. If you don't get the prompt, or if the hosts file opens in another program, open Notepad (Start, All Programs, Accessories, Notepad), and then navigate to hosts by clicking File, Open within Notepad.
3. Place the cursor at the end of the last line, which will say something such as '127.0.0.1 localhost' or '::1 localhost'. Press Enter to create a new line.
4. Type 127.0.0.1, tap the spacebar once, and then type the address of a website you want to block. For example, to block all traffic from YouTube, type 127.0.0.1 www.youtube.com on this line.
5. Continue to add the websites you wish to block, each prefaced with 127.0.0.1 and a space.
6. Click File, Save to commit to your changes. Dismiss any warnings from antimalware software, which may be triggered by your editing of the hosts file.
7. Close any open browser windows, and then reopen a browser to test your edits. The blocked sites should not display in any browser.